Question

what happens to the acceleration of a given object if the net force acting on it is doubled? double the original quadruple the original stays the same becomes half of the original becomes one - quarter of the original

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration. We can solve for \(a\) to get \(a=\frac{F}{m}\).

Step2: Analyze the case when force is doubled

Let the initial force be \(F_1\) and the initial acceleration be \(a_1=\frac{F_1}{m}\). When the force is doubled (\(F_2 = 2F_1\)), the new acceleration \(a_2=\frac{F_2}{m}\). Substitute \(F_2 = 2F_1\) into the formula for \(a_2\), we get \(a_2=\frac{2F_1}{m}\). Since \(a_1=\frac{F_1}{m}\), then \(a_2 = 2a_1\).

Answer:

Double the original