Question

1. what is the change in velocity for an object that accelerates at 4 m/s² for 3 seconds? 7 m/s 3 m/s² 12 m/s 1.33 m/s²

Explanation:

Step1: Recall acceleration - velocity - time formula

The formula for acceleration $a=\frac{\Delta v}{\Delta t}$, where $a$ is acceleration, $\Delta v$ is change in velocity and $\Delta t$ is change in time. We can re - arrange it to find $\Delta v=a\times\Delta t$.

Step2: Substitute given values

Given $a = 4\ m/s^{2}$ and $\Delta t=3\ s$. Then $\Delta v=4\ m/s^{2}\times3\ s$.

Step3: Calculate result

$\Delta v = 12\ m/s$.

Answer:

C. 12 m/s