Question

what is the approximate energy of a photon having a frequency of 4 × 10^7 hz? (h = 6.6 × 10^-34 js)
○ 2 × 10^-41 j
○ 3 × 10^-26 j
○ 3 × 10^-27 j
○ 3 × 10^42 j

Explanation:

Step1: Use the formula for photon energy

The formula for the energy of a photon is \(E = h
u\), where \(h = 6.6\times10^{-34}\text{ Js}\) (Planck's constant) and \(
u\) is the frequency. Given \(
u=4\times 10^{7}\text{ Hz}\).

Step2: Substitute the values into the formula

\(E=(6.6\times 10^{-34}\text{ Js})\times(4\times 10^{7}\text{ Hz})\)

$$
LATEXBLOCK0
$$

Answer:

\(3\times 10^{-26}\text{ J}\) (corresponding to the option \(3\times 10^{-26}\text{ J}\))