Question

1. what is the acceleration of a 650 kg racing camel that has a forward net force of 897 n?

m :
a :
f :

Explanation:

Step1: Identify the formula

Newton's second law \(F = ma\), so \(a=\frac{F}{m}\)

Step2: Substitute the values

Given \(F = 897\space N\) and \(m = 650\space kg\), then \(a=\frac{897}{650}\)

Step3: Calculate the acceleration

\(a = 1.38\space m/s^{2}\)

Answer:

The acceleration of the racing camel is \(1.38\space m/s^{2}\)