Question

what is the acceleration of a 32 kg object if a 6.75 n force is applied to it?
0.21 m/s²
4.74 m/s²
21.09 m/s²
216.00 m/s²

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is force, \(m\) is mass, and \(a\) is acceleration. We need to solve for \(a\), so the formula becomes \(a=\frac{F}{m}\).

Step2: Substitute the given values

Given \(F = 6.75\space N\) and \(m = 32\space kg\). Substitute into the formula: \(a=\frac{6.75}{32}\).

Step3: Calculate the value

\(a=\frac{6.75}{32}= 0.2109375\approx0.21\space m/s^{2}\)

Answer:

\(0.21\space m/s^{2}\) (the first option)