Question

a weightlifter is holding a 200 - kg barbell at a height of 1 meter above the ground. how much work is he performing while holding the barbell still? ______ joules enter the answer

Explanation:

Step1: Recall the work formula

Work \(W = F\times d\times\cos\theta\), where \(F\) is the force, \(d\) is the displacement, and \(\theta\) is the angle between the force and displacement.

Step2: Analyze the situation

When the weightlifter holds the barbell still, the displacement \(d = 0\) (the barbell does not move).

Answer:

\(0\)