Question

if we start off with element $_{24}x^{50}$ after an alpha decay we get another element y that looks like

Explanation:

Step1: Alpha decay formula

In alpha decay, the mass number \(A\) decreases by \(4\) and the atomic number \(Z\) decreases by \(2\). The general formula for alpha decay is \(_{Z}^{A}X
ightarrow_{Z - 2}^{A-4}Y+_{2}^{4}He\)

Step2: Calculate for given element

Given \(_{24}^{50}X\), after alpha decay:

• Atomic number of \(Y\): \(Z_Y=24 - 2=22\)
• Mass number of \(Y\): \(A_Y=50 - 4 = 46\)

Answer:

\(_{22}^{46}Y\) (i.e., the first option \(22Y^{46}\))