use the following table to answer question 44.
gas analysis of products of coke - oven gas burning
co: 6.8%
h₂: 47.3%
ch₄: 33.9%
co₂: 2.2%
n₂: 6.0%
other: 3.8%
44. calculate degrees how many degrees of a circle graph would represent carbon mon - oxide (co)? how many degrees would represent methane (ch₄)?
45. calculate the density of a cube of lead that has sides of 10 cm and a mass of 11.34 kg.
46. use numbers a nanotube has a diameter of about one - billionth of a meter. how many nanotubes would you have to stack to get the thickness of a copper wire with a 0.65 mm diameter?

Question

Accepted Answer

### Question 44
# Explanation:
## Step1: Formula for degrees in a circle graph
The formula to find the degrees for a component in a circle graph is $ \text{Degrees}=\text{Percentage}\times360^{\circ}$

## Step2: Calculate degrees for $CO$
Given the percentage of $CO = 6.8\%$. Using the formula $ \text{Degrees}=6.8\%\times360^{\circ}$
$$
\begin{align*}
\text{Degrees}&=\frac{6.8}{100}\times360^{\circ}\
&= 6.8\times3.6^{\circ}\
&=24.48^{\circ}
\end{align*}
$$

## Step3: Calculate degrees for $CH_{4}$
Given the percentage of $CH_{4}=33.9\%$. Using the formula $ \text{Degrees}=33.9\%\times360^{\circ}$
$$
\begin{align*}
\text{Degrees}&=\frac{33.9}{100}\times360^{\circ}\
&=33.9\times3.6^{\circ}\
& = 122.04^{\circ}
\end{align*}
$$

# Answer:
Carbon monoxide ($CO$): $24.48^{\circ}$, Methane ($CH_{4}$): $122.04^{\circ}$

### Question 45
# Explanation:
## Step1: Calculate the volume of the cube
The volume $V$ of a cube with side length $s$ is $V = s^{3}$. Given $s = 10\space cm$, so $V=(10\space cm)^{3}=1000\space cm^{3}$

## Step2: Convert mass to grams
Given mass $m = 11.34\space kg$. Since $1\space kg=1000\space g$, then $m = 11.34\times1000\space g=11340\space g$

## Step3: Calculate density
The formula for density $
ho$ is $
ho=\frac{m}{V}$. Substituting $m = 11340\space g$ and $V = 1000\space cm^{3}$
$$

ho=\frac{11340\space g}{1000\space cm^{3}} = 11.34\space g/cm^{3}
$$

# Answer:
$11.34\space g/cm^{3}$

### Question 46
# Explanation:
## Step1: Convert units
The diameter of the nanotube $d_{n}=1\times10^{-9}\space m$. The diameter of the copper wire $d_{c}=0.65\space mm = 0.65\times10^{-3}\space m$

## Step2: Calculate the number of nanotubes
The number of nanotubes $n=\frac{d_{c}}{d_{n}}$
$$
n=\frac{0.65\times 10^{-3}\space m}{1\times10^{-9}\space m}=6.5\times10^{5}
$$

# Answer:
$6.5\times 10^{5}$

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QUESTION IMAGE

Question

Explanation:

Question 44

Step1: Formula for degrees in a circle graph

Step2: Calculate degrees for \(CO\)

Step3: Calculate degrees for \(CH_{4}\)

Step1: Calculate the volume of the cube

Step2: Convert mass to grams

Step3: Calculate density

Step1: Convert units

Step2: Calculate the number of nanotubes

Answer:

Question 45