Question

1
type the correct answer in each box.
light travels at a speed of 3.0 × 10^8 meters/second.
if you used a calculator to find the distance light travels in 4,500 seconds, you would get
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Explanation:

Step1: Use the formula \(d = vt\) (distance = velocity×time)

Here, \(v = 3.0\times10^{8}\) meters/second and \(t = 4500\) seconds.

Step2: Substitute the values into the formula

\(d=(3.0\times 10^{8})\times4500\)
First, \(4500 = 4.5\times10^{3}\)
So, \(d=(3.0\times 10^{8})\times(4.5\times 10^{3})\)
Using the rule \(a^{m}\times a^{n}=a^{m + n}\) and \((a\times b)\times(c\times d)=(a\times c)\times(b\times d)\)
\(d=(3.0\times4.5)\times(10^{8}\times10^{3})\)
\(3.0\times4.5 = 13.5\) and \(10^{8}\times10^{3}=10^{8 + 3}=10^{11}\)
So, \(d = 13.5\times10^{11}\)
In scientific notation, \(d=1.35\times10^{12}\) meters

Answer:

\(1.35\times10^{12}\)