two parallel plates with an area of $0.155\text{ m}^2$ are separated by $1.00 \times 10^{-3}\text{ m}$.

what is their capacitance?

$ ? \times 10^{ ? }\text{ f}$

Question

two parallel plates with an area of $0.155\text{ m}^2$ are separated by $1.00 \times 10^{-3}\text{ m}$.

what is their capacitance?

$ ?  \times 10^{ ? }\text{ f}$

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Parallel Plate Capacitor", "Capacitance" ], "new_concepts": [], "current_concepts": [ "Parallel Plate Capacitor", "Capacitance" ] } ## Identify given parameters $$ \begin{aligned} A &= 0.155\text{ m}^2\ d &= 1.00 \times 10^{-3}\text{ m}\ \varepsilon_0 &\approx 8.854 \times 10^{-12}\text{ F/m} \end{aligned} $$ ## Calculate capacitance $$ \begin{aligned} C &= \frac{\varepsilon_0 A}{d}\ C &= \frac{(8.854 \times 10^{-12}\text{ F/m})(0.155\text{ m}^2)}{1.00 \times 10^{-3}\text{ m}}\ C &\approx 1.372 \times 10^{-9}\text{ F} \end{aligned} $$ ## Format in scientific notation $$ C \approx 1.37 \times 10^{-9}\text{ F} $$ Two parallel plates with an area of $0.155\text{ m}^2$ are separated by $1.00 \times 10^{-3}\text{ m}$. What is their capacitance? $1.37$ $\times 10^{\text{ }}$$-9$ $\text{F}$ { "subject": "Natural Science", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Natural Science", "Physics", "Capacitance" ] }

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Question

Explanation:

Identify given parameters

Calculate capacitance

Format in scientific notation

Answer: