Question

truck with a mass of 2,000 kg is initially at rest. it accelerates to a speed of 20 m/s over 10 seconds. what is the impulse delivered to the truck?
20,000 n·s
30,000 n·s
40,000 n·s
50,000 n·s

Explanation:

Step1: Recall the impulse - momentum theorem

Impulse \(J\) is equal to the change in momentum \(\Delta p\). The formula for momentum is \(p = mv\). The initial velocity \(v_{i}=0\) (truck is initially at rest), and the final velocity \(v_{f} = 20\space m/s\), mass \(m = 2000\space kg\).

Step2: Calculate the change in momentum

\(\Delta p=m(v_{f}-v_{i})\). Substitute \(m = 2000\space kg\), \(v_{i}=0\space m/s\), \(v_{f}=20\space m/s\) into the formula. Then \(\Delta p=2000\times(20 - 0)\).

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Answer:

C. \(40,000\space N\cdot s\)