Question

a train travels with a constant speed of 30.0m/s for 6.00s. determine all unknowns and answer the following question(s). what is the magnitude of the trains acceleration? how far did the train travel during this time?

Explanation:

Step1: Find the acceleration

Since the train is moving with a constant speed, the change in velocity \(\Delta v = 0\).
The formula for acceleration is \(a=\frac{\Delta v}{\Delta t}\).
Substituting \(\Delta v = 0\) into the formula, we get \(a=\frac{0}{\Delta t}=0\space m/s^{2}\).

Step2: Find the distance traveled

The formula for distance when speed \(v\) is constant is \(d = v\times t\).
Given \(v = 30.0\space m/s\) and \(t=6.00\space s\).
Substitute the values into the formula: \(d=(30.0\space m/s)\times(6.00\space s)\)
\(d = 180\space m\)

Answer:

The magnitude of the train's acceleration is \(0\space m/s^{2}\).
The train traveled \(180\space m\) during this time.