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question 2
in the produce section of a supermarket, pears are placed on a spring scale. the placement of the pears stretches the spring and causes the dial to move from zero to a reading of 2.0 kg. if the spring constant is 450 n/m, what is the displacement of the spring due to the weight of the pears?
0.044 m
0.0088 m
0.018 m
0.0044 m
0.088 m

Explanation:

Step1: Calculate weight of pears

Weight $W = mg = 2.0\,\text{kg} \times 9.8\,\text{m/s}^2 = 19.6\,\text{N}$

Step2: Use Hooke's Law for displacement

Displacement $x = \frac{W}{k} = \frac{19.6\,\text{N}}{450\,\text{N/m}} \approx 0.0436\,\text{m} \approx 0.044\,\text{m}$

Answer:

0.044 m