Question

3.3.2 test (cst): forces
question 2 of 20
you pull a sled with a package on it across a snow - covered flat lawn. if you apply a force of 46.8 n to the sled, it accelerates at 0.75 m/s². what is the combined mass of the package and the sled? (assume there is no friction.)
a. 35.10 kg
b. 96.75 kg
c. 52.50 kg
d. 62.40 kg

Explanation:

Step1: Apply Newton's second law

Newton's second law is \(F = ma\), where \(F\) is the force, \(m\) is the mass, and \(a\) is the acceleration. We need to solve for \(m\), so we can rewrite the formula as \(m=\frac{F}{a}\).

Step2: Substitute the given values

We are given that \(F = 46.8\space N\) and \(a=0.75\space m/s^{2}\). Substituting these values into the formula \(m=\frac{F}{a}\), we get \(m=\frac{46.8}{0.75}\).

Step3: Calculate the mass

\(m=\frac{46.8}{0.75}=62.4\space kg\)

Answer:

D. \(62.40\space kg\)