Question

students had two batteries and two different resistors. during four trials, they build four different circuits and plan measure the circuits current in amps according to the following table:
for which trial would the students measure the smallest current in the circuit?
trial 1
trial 2
trial 3
trial 4

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is \(I=\frac{V}{R}\), where \(I\) is current, \(V\) is voltage, and \(R\) is resistance.

Step2: Calculate current for each trial

• Trial 1: \(I_1=\frac{V_1}{R_1}=\frac{1.5}{200}= 0.0075\space A\)
• Trial 2: \(I_2=\frac{V_2}{R_2}=\frac{1.5}{100}=0.015\space A\)
• Trial 3: \(I_3=\frac{V_3}{R_3}=\frac{3.0}{200}=0.015\space A\)
• Trial 4: \(I_4=\frac{V_4}{R_4}=\frac{3.0}{100}=0.03\space A\)

Answer:

A. Trial 1