Question

a student connects two aa batteries each battery is 1.5 volts in series to light up a light bulb. the circuit has a resistance of 6ω. how much current flows through the circuit? 75 a 1 a 300 a 0.5 a

Explanation:

Step1: Calculate the total voltage

Each AA battery has a voltage \(V = 1.5\ \text{V}\). If there are two batteries in series, the total voltage \(V_{total}=1.5\ \text{V}+ 1.5\ \text{V}=3\ \text{V}\)

Step2: Apply Ohm's Law

Ohm's Law is \(I=\frac{V}{R}\), where \(V = 3\ \text{V}\) and \(R = 100\ \Omega\). Then \(I=\frac{3\ \text{V}}{100\ \Omega}=0.03\ \text{A}\)

Answer:

D. \(0.03\ \text{A}\)