Question

if a student calculates the volume of a cylinder as 1.24 l, but the actual volume of the cylinder is 1.53 l, what is the percent error for the calculation? a) 23.4% b) 81.0% c) 13.5% d) 19.0% e) 12.7%

Explanation:

Step1: Recall the formula for percent error

Percent error = $\frac{\vert\text{Experimental Value}-\text{Actual Value}\vert}{\text{Actual Value}}\times100\%$

Step2: Identify the values

Experimental value = $1.24$ L, Actual value = $1.53$ L

Step3: Substitute into the formula

Percent error = $\frac{\vert1.24 - 1.53\vert}{1.53}\times100\%=\frac{0.29}{1.53}\times100\%$

Step4: Calculate the result

$\frac{0.29}{1.53}\times100\%\approx18.95\%\approx19.0\%$

Answer:

d) 19.0%