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Question
sprockets practice problems
pulleys and belts
in a pulley system, pulley a is moving at 1500 rpm and has a diameter of 15 in. three pulleys, b, c, and d, all of different sizes, are attached to a single output axle. speed and torque output are changed within the system by moving the drive belt between pulleys b, c, and d.
- sketch and annotate the drive train described above.
- a speed of 1750 rpm is required when the drive belt is connected to pulley b. what is the diameter of pulley b?
- a speed of 2000 rpm is required when the drive belt is connected to pulley c. what is the diameter of pulley c?
Step1: Write the formula for pulley speed - diameter relationship
The relationship between pulley diameters (\(d\)) and rotational speeds (\(n\)) is given by \(d_1n_1=d_2n_2\). Here, \(d_1 = 15\) in, \(n_1=1500\) rpm, and \(n_2 = 2000\) rpm. We need to find \(d_2\) (diameter of pulley \(C\)).
Step2: Substitute the values into the formula
Substitute the values into \(d_1n_1=d_2n_2\). So, \(15\times1500=d_2\times2000\).
Step3: Solve for \(d_2\)
First, calculate \(15\times1500 = 22500\). Then, \(d_2=\frac{22500}{2000}\). Simplifying \(\frac{22500}{2000}=\frac{225}{20}= 11.25\) in.
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The diameter of pulley \(C\) is \(11.25\) in.