Question

the speed of an object undergoing constant acceleration increases from 8.0 m/s to 16.0 m/s in 10 s. how far does the object travel during the 10 seconds? 360 m 120 m 80. m 160 m

Explanation:

Step1: Find the average speed

The formula for average speed $\bar{v}$ when acceleration is constant is $\bar{v}=\frac{v_i + v_f}{2}$, where $v_i$ is the initial - speed and $v_f$ is the final speed. Given $v_i = 8.0\ m/s$ and $v_f=16.0\ m/s$. So, $\bar{v}=\frac{8.0 + 16.0}{2}=\frac{24.0}{2}=12.0\ m/s$.

Step2: Calculate the distance

The formula for distance $d$ is $d=\bar{v}\times t$, where $t$ is the time. Given $t = 10\ s$ and $\bar{v}=12.0\ m/s$. Then $d=12.0\times10 = 120\ m$.

Answer:

120 m