Question

specific gravity is the ratio, as a decimal, of the density of a substance to the density of water. density is the ratio of the mass to the volume. the mass of 760 gallons of fuel is 2325 kilograms (kg). a single gallon of water has a mass of about 3.8 kg. to the nearest tenth, what is the specific gravity of jet fuel?

Explanation:

Step1: Calculate the density of the fuel

Density formula: $\text{Density}=\frac{\text{Mass}}{\text{Volume}}$.
The mass of the fuel is $m = 2325$ kg and the volume $V=760$ gallons.
So, the density of the fuel $
ho_{fuel}=\frac{2325}{760}$ kg/gallon.

$$ ho_{fuel}=\frac{2325}{760}\approx3.06\ \text{kg/gallon} $$

Step2: Calculate the density of water

Given that the mass of 1 gallon of water is $m_{water} = 3.8$ kg. Using the density formula $\text{Density}=\frac{\text{Mass}}{\text{Volume}}$, for water with $V = 1$ gallon, the density of water $
ho_{water}=\frac{3.8}{1}=3.8$ kg/gallon.

Step3: Calculate the specific gravity

Specific gravity formula: $\text{Specific Gravity}=\frac{\text{Density of Substance}}{\text{Density of Water}}$.
Substitute $
ho_{fuel}\approx3.06$ kg/gallon and $
ho_{water}=3.8$ kg/gallon into the formula.

$$ \text{Specific Gravity}=\frac{3.06}{3.8}\approx0.8 $$

Answer:

$0.8$