Question

the silcion diodes circuit, assume $i_{o}=3ma$. which values of $i_{o}$,the ratio of $v_{o2}/v_{s}$ is $1/5$?
a. 1.0 ma
b. 4.5 ma
c. 3.0 ma
d. 1.5 ma

Explanation:

Step1: Analyze the circuit operation

Assume the diodes are ideal. When considering the voltage - current relationships in the circuit, we can use the principle of current division and voltage drops across components.

Step2: Establish the relationship between voltages and currents

Let's analyze the circuit in terms of current flowing through different paths. The current source of 6 mA divides between the paths related to the diodes and the load. The output voltage \(v_{o2}\) and input voltage \(v_s\) are related to the current - voltage characteristics of the diodes and the current \(I_O\). For a simple diode - based circuit like this, we can use the fact that the voltage across a conducting diode is approximately 0 V (ideal case). Let's consider the current flow through the circuit. The current through the path related to \(v_{o2}\) is affected by \(I_O\). The total current of 6 mA is split. Let's assume the current through the path contributing to \(v_{o2}\) is \(I_{o2}\). We know that \(v_{o2}\) is proportional to \(I_{o2}\) and \(v_s\) is related to the overall current and circuit elements. By analyzing the current - division and voltage - current relationships in the circuit, we find that when \(I_O = 1.5\ mA\), the ratio \(\frac{v_{o2}}{v_s}=\frac{1}{5}\).

Answer:

D. 1.5 mA