Question

5 several springs are lying on frictionless tabletops with one end attached to a wall and a variable force f applied to the free end of each spring. the springs have different spring constants, k. the diagram below shows the setup for one of the springs. the elongation of the springs produced by force f depends a directly on both f and k c inversely on f and directly on k b directly on f and inversely on k d inversely on both f and k

Explanation:

Step1: Recall Hooke's Law

Hooke's Law is given by \(F = kx\), where \(F\) is the force applied, \(k\) is the spring - constant, and \(x\) is the elongation of the spring.

Step2: Solve for \(x\)

From \(F = kx\), we can solve for \(x\) as \(x=\frac{F}{k}\).

Answer:

B. directly on \(F\) and inversely on \(k\)