Question

select the correct answer from the drop - down menu. the design for a two - tank system is shown. the inner tank must be surrounded by oxygen with a density of 0.0827 pounds per cubic foot. what amount of oxygen is needed in the outer tank? to meet the density required, approximately drop - down pounds of oxygen is required.

Explanation:

Step1: Calculate the volume of the outer tank

The volume of a rectangular prism is \(V = l\times w\times h\). For the outer - tank, \(l = 20\) ft, \(w = 8\) ft, \(h = 6\) ft. So \(V_{outer}=20\times8\times6=960\) cubic feet.

Step2: Calculate the volume of the inner tank

For the inner - tank, \(l = 5\) ft, \(w = 4\) ft, \(h = 3\) ft. So \(V_{inner}=5\times4\times3 = 60\) cubic feet.

Step3: Calculate the volume of the space for oxygen

\(V = V_{outer}-V_{inner}\). Substitute the values: \(V=960 - 60=900\) cubic feet.

Step4: Calculate the mass of oxygen

We know that density \(
ho=\frac{m}{V}\), so \(m=
ho\times V\). Given \(
ho = 0.0827\) pounds per cubic foot and \(V = 900\) cubic feet. Then \(m=0.0827\times900 = 74.43\) pounds.

Answer:

\(74.43\)