Question

1 roland is pulling a box of supplies out of a storage closet. the box has a mass of 220 kg, and the coefficient of friction between the box and the ground is 0.17. when the box is sliding, what is the magnitude of the force of friction?
$f_{f}=37.4n$
$f_{f}=367n$
$f_{f}=220n$
$f_{f}=419n$

Explanation:

Step1: Calculate the normal force

The normal force \(F_N\) on a horizontal surface is equal to the weight of the object. Using the formula \(F_N = mg\), where \(m = 220\space kg\) and \(g= 9.8\space m/s^{2}\).
\(F_N=220\times9.8 = 2156\space N\)

Step2: Calculate the force of friction

The formula for the force of friction is \(F_f=\mu F_N\), where \(\mu = 0.17\) and \(F_N = 2156\space N\)
\(F_f=0.17\times2156\)
\(F_f = 366.52\approx367\space N\)

Answer:

\(F_f = 367\space N\) (the second option)