Question

6 in an rl series circuit, as the phase angle approaches 90 degrees, the circuit is mostly

a inductive

b resistive

c capacitive

d neither, r and l are balanced (equal)

Explanation:

In an RL series circuit, the phase angle formula is $\tan\varphi=\frac{X_{L}}{R}$ (where $X_{L}$ is inductive reactance and $R$ is resistance). As $\varphi
ightarrow90^{\circ}$, $\tan\varphi
ightarrow\infty$. This implies that $X_{L}\gg R$. When inductive reactance is much larger than resistance, the circuit is dominated by inductive characteristics. A resistive circuit would have $\varphi = 0^{\circ}$ ($X_{L}=0$), a capacitive circuit is not relevant here (since it's an RL - not RC circuit), and if $R$ and $L$ were balanced ($X_{L}=R$), $\varphi = 45^{\circ}$.

Answer:

A. inductive