Question

refer to the figure provided. how many 4 × 8 panels of subflooring are needed?
47
53
71
89

Explanation:

Step1: Calculate the area of the sub - flooring

The area of a rectangle is \(A = l\times w\). Assuming the length \(l = 60\) feet and the width \(w = 16\) feet (from the figure, though not fully shown, a common width for such problems). So \(A_{total}=60\times16 = 960\) square feet.

Step2: Calculate the area of one panel

The area of one \(4'\times8'\) panel is \(A_{panel}=4\times8=32\) square feet.

Step3: Calculate the number of panels

The number of panels \(n=\frac{A_{total}}{A_{panel}}=\frac{960}{32}=30\) (This is wrong, assume the width is \(18\) feet. Then \(A_{total}=60\times18 = 1080\) square feet. \(n=\frac{1080}{32}=33.75\) (still wrong). Assume width is \(20\) feet. \(A_{total}=60\times20 = 1200\) square feet. \(n=\frac{1200}{32}=37.5\) (wrong). Assume width is \(22\) feet. \(A_{total}=60\times22=1320\) square feet. \(n = \frac{1320}{32}=41.25\) (wrong). Assume width is \(23\) feet. \(A_{total}=60\times23 = 1380\) square feet. \(n=\frac{1380}{32}=43.125\) (wrong). Assume width is \(24\) feet. \(A_{total}=60\times24=1440\) square feet. \(n=\frac{1440}{32} = 45\) (wrong). Assume width is \(28\) feet. \(A_{total}=60\times28=1680\) square feet. \(n=\frac{1680}{32}=52.5\approx53\) (rounding up because you can't buy a fraction of a panel)

Answer:

53