Question

record amartinez@students.westerlyps.org as the email to be included with my response
scenerio
nfl wide receiver, justin jefferson runs downfield 20 m facing north. he turns east and runs another 8 m. he quickly cuts south and runs 2 m back towards the line of scrimmage where he catches the pass.
what distance did justin jefferson travel during this route?
1 point
30km
what was justin jefferson displacement by the end of the route?
1 point
your answer

Explanation:

Step1: Calculate the distance

Distance is the total length of the path traveled.

$$20 + 8+2=30\space m$$

Step2: Calculate the displacement

Displacement is the straight - line distance from the starting point to the ending point.
North - south displacement: \(20 - 2=18\space m\) (north)
East - west displacement: \(8\space m\) (east)
Using the Pythagorean theorem \(d=\sqrt{18^{2}+8^{2}}=\sqrt{324 + 64}=\sqrt{388}\approx19.7\space m\)

Answer:

Distance: \(30\space m\)
Displacement: Approximately \(19.7\space m\)