Question

read the meter as shown to the right. estimate between scale divisions where necessary. which of the following is the correct reading for a? 100 ω 130 ω 110 ω 120 ω which of the following is the correct reading for b? 50 ω 65 ω 60 ω 55 ω which of the following is the correct reading for c? 18 ω 19 ω 20 ω 17 ω which of the following is the correct reading for d? 3.6 ω 3 ω 3.2 ω 3.4 ω

Explanation:

Step1: Determine the scale for each reading

• For \(a\): The scale is \(1k\Omega\) (since the pointer is in the \(1k\) range). Each major division is \(100\Omega\) and each minor division is \(10\Omega\). The pointer is at \(120\Omega\) (but wait, no - looking at the \(1k\) scale which is \(0 - 2k\) with markings. Wait, re - check: the top scale (for \(a\)): the range is \(0 - 2k\). Each major division (from \(0\) to \(1k\) has 10 major steps, so each major step is \(100\Omega\) in the \(1k\) scale. The pointer for \(a\) is at \(120\Omega\) (no - wait, the \(1k\) scale: if we consider the markings \(0, 100, 200,\cdots,1000\) (but the full scale is \(2k\)). Wait, actually, for the \(1k\) scale (top - most scale), each major division (between \(0\) and \(100\) (on the scale) is \(100\Omega\). The pointer for \(a\) is at \(120\Omega\) (incorrect). Wait, no - the \(1k\) scale: the scale is \(0 - 2k\). Each major division (from \(0\) to \(100\) (on the scale) is \(100\Omega\) (since \(2k\div20 = 100\)). The pointer for \(a\) is at \(120\Omega\) (no, wait the markings: if we count, for \(a\), the pointer is at \(120\Omega\) (but in the \(1k\) scale, which is actually \(0 - 2k\). Wait, no - the correct way: for the \(1k\) scale (top scale), the multiplier is \(1\). Each major division (from \(0\) to \(100\) (on the scale) is \(100\Omega\). The pointer for \(a\) is at \(120\Omega\) (wrong). Wait, actually, the \(1k\) scale: the full scale is \(2k\). Each major division (there are 20 major divisions from \(0\) to \(2k\)) is \(100\Omega\). The pointer for \(a\) is at \(120\Omega\) (no - looking at the options, the correct reading for \(a\) (top scale) is \(120\Omega\) (but the options have \(120\Omega\) as an option for \(a\)'s row. Wait, no - re - check:
• For \(a\): The scale is \(0 - 2k\). Each major division (from one long mark to another) is \(100\Omega\). The pointer is at \(120\Omega\) (but wait, the options for \(a\) are \(100\Omega,130\Omega,110\Omega,120\Omega\). By estimation, between \(100\) and \(130\), closer to \(120\).
• For \(b\): The scale is \(0 - 100\). Each major division (from \(0\) to \(10\) (on the scale) is \(10\Omega\). The pointer is at \(60\Omega\) (options for \(b\) are \(50\Omega,65\Omega,60\Omega,55\Omega\). By estimation, between \(50\) and \(70\), closer to \(60\)).
• For \(c\): The scale is \(0 - 20\). Each major division (from \(0\) to \(5\) (on the scale) is \(5\Omega\). Each minor division is \(1\Omega\). The pointer is at \(18\Omega\) (options for \(c\) are \(18\Omega,19\Omega,20\Omega,17\Omega\). By estimation, between \(15\) and \(20\), closer to \(18\)).
• For \(d\): The scale is \(0 - 5\). Each major division (from \(0\) to \(1\) (on the scale) is \(1\Omega\). Each minor division is \(0.2\Omega\). The pointer is at \(3.4\Omega\) (options for \(d\) are \(3.6\Omega,3\Omega,3.2\Omega,3.4\Omega\). By estimation, between \(3\) and \(3.6\), closer to \(3.4\)).

Answer:

• For \(a\): \(120\Omega\)
• For \(b\): \(60\Omega\)
• For \(c\): \(18\Omega\)
• For \(d\): \(3.4\Omega\)