Question

quiz instructions
you can complete this review up to 3 times. it will be worth 2.5 points extra credit onto the exam.
question 8
1 pts
a hockey puck slides at a constant velocity across a frictionless ice rink. the ice exerts a normal force on the puck equal to 5.5 newtons. what must be the weight of the puck?

Explanation:

Step1: Analyze forces on the puck

The hockey puck is on a horizontal, frictionless ice rink and moving at constant velocity. So, in the vertical direction, the net force is zero (Newton's first law, equilibrium).

Step2: Relate normal force and weight

The normal force (\(F_N\)) from the ice on the puck and the weight (\(W\)) of the puck are the only vertical forces. For equilibrium, \(F_N = W\) (since normal force upward balances weight downward).

Step3: Determine the weight

Given \(F_N = 5.5\) Newtons, so \(W = F_N = 5.5\) Newtons.

Answer:

5.5 Newtons