Question

question 8
what is y after the following switch statement is executed?
int x = 3; int y = 4;
switch (x + 3) {
case 6: y = 0;
case 7: y = 1;
default: y += 2;
}
a 2
b 1
c 4
d 3
e 0

Explanation:

Step1: Calculate the value of \(x + 3\)

Given \(x = 3\), then \(x+3=3 + 3=6\).

Step2: Analyze the switch - case statement

The switch expression is \(6\). There is no case 6 in the given code. The code will then check the default case.

Step3: Execute the default case

The default case has the statement \(y+=2\). Initially, \(y = 4\). After \(y=y + 2\), \(y=4+2=6\). Wait, there is a mistake. Let's re - analyze:
Wait, no! Let's check again. The code is:

int x = 3;
int y = 4;
switch(x + 3){
    case 6: y = 0;
    case 7: y = 1;
    default: y += 2;
}

The switch expression \(x + 3=6\). When case 6 is executed, \(y = 0\). But in Java (assuming it's Java - like syntax), if there is no break statement, it will fall through. After case 6: y = 0; (no break), it will execute default: y += 2; (because after case 6 there is no break, and there is no case 7 which is not relevant here). So \(y=0+2=2\).

Answer:

A. 2