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Question
question 6
suppose ( x = 1,y=-1 ), and ( z = 1 ). what is the output of the following statement? (please indent the statement correctly first.)
if ( (x>0) )
if ( (y>0) )
system.out.println(\x > 0 and y > 0\);
else if ( (z>0) )
system.out.println(\x < 0 and z > 0\);
a no output.
b ( x < 0 ) and ( z < 0 );
c ( x > 0 ) and ( y > 0 );
d ( x < 0 ) and ( z > 0 );
Step1: Analyze the first if condition
The first condition is if (x > 0). Given \(x = 1\), \(1>0\) is true.
Step2: Analyze the nested if condition
The nested condition is if (y > 0). Given \(y=- 1\), \(-1>0\) is false. So the System.out.println("x > 0 and y > 0"); statement is not executed.
Step3: Analyze the else - if condition
Since the nested if (inside the first if) is false, we check the else if (z > 0) in the original code (after proper indentation). But in Java, the else if is part of the outer if - else structure only if properly indented. Here, the correct indentation would make the else if belong to the outer if. However, when the nested if (inside the first if) fails, and there is no else for the outer if (assuming correct block scoping), and no other applicable print statements.
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A. no output.