question 5
6 points
consider a block of mass 800 g on a horizontal surface. the block it pushed with the force of 3n. if the acceleration of the block is 1.5 m/s², what is the coefficient of kinetic friction between the mass and the surface?
add your answer
integer, decimal or e notation allowed

Question

Accepted Answer

# Explanation:
## Step1: Convert mass to kg
Given mass $m = 800g=0.8kg$
## Step2: Apply Newton's second law $F_{net}=ma$
The net force $F_{net}=F - f$, where $F = 3N$ is the applied force and $f=\mu_{k}N$ is the kinetic - friction force. On a horizontal surface, $N = mg$ (normal force equals weight). So $F_{net}=F-\mu_{k}mg$ and $F_{net}=ma$. Then $F-\mu_{k}mg=ma$
## Step3: Solve for $\mu_{k}$
Rearrange the equation $F-\mu_{k}mg = ma$ for $\mu_{k}$:
$$
\begin{align*}
\mu_{k}mg&=F - ma\
\mu_{k}&=\frac{F - ma}{mg}
\end{align*}
$$
Substitute $F = 3N$, $m = 0.8kg$, $a=1.5m/s^{2}$, $g = 9.8m/s^{2}$
$$
\begin{align*}
\mu_{k}&=\frac{3-(0.8\times1.5)}{0.8\times9.8}\
&=\frac{3 - 1.2}{7.84}\
&=\frac{1.8}{7.84}\
&\approx0.23
\end{align*}
$$

# Answer:
$0.23$

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Step1: Convert mass to kg

Step2: Apply Newton's second law \(F_{net}=ma\)

Step3: Solve for \(\mu_{k}\)

Answer: