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question 2 (1 point) if a student calculates the volume of a cylinder a…

Question

question 2 (1 point)
if a student calculates the volume of a cylinder as 1.24 l, but the actual volume of the cylinder is 1.53 l, what is the percent error for the calculation?
a) 24.7%
b) 81.0%
c) 19.0%
d) 94.6%
e) 17.6%

Explanation:

Step1: Recall the formula for percent error

The formula for percent error is $Percent\ Error=\frac{\vert Estimated\ Value - Actual\ Value\vert}{Actual\ Value}\times100\%$.

Step2: Identify the estimated and actual values

Here, the estimated value is $1.24$ L and the actual value is $1.53$ L.

Step3: Substitute values into the formula

First, find the difference: $\vert1.24 - 1.53\vert=\vert- 0.29\vert = 0.29$. Then, calculate the fraction: $\frac{0.29}{1.53}\approx0.19$. Finally, multiply by 100%: $0.19\times100\% = 19.0\%$.

Answer:

C. 19.0%