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question 7 (1 point) saving... when pressure i and volume ii the reaction in an equilibrium system shifts in the direction that produces iii particles. the statement given above is completed by the information given in the row: table with rows a - e, columns i, ii, iii options: a, b, c, d, e. internet connection lost. no longer saving answers. when the time limit is up, answers saved before your connection was lost will be submitted automatically.
To solve this, we use Le Chatelier's principle for gas equilibrium. Pressure and volume are inversely related (Boyle's law: \(P \propto \frac{1}{V}\)). When pressure (i) increases, volume (ii) decreases. The system shifts to reduce pressure, so it moves toward the side with fewer moles? Wait, no—wait, if pressure increases (volume decreases), the system shifts to the side with fewer gas particles? Wait, no, the question says "produces more particles" in row B. Wait, no, let's re-examine. Wait, when pressure increases (volume decreases), the system shifts to the side with fewer moles (particles) to reduce pressure. But row B says "produces more"—wait, maybe I made a mistake. Wait, no, let's check the options again. Wait, the correct principle: for a gas equilibrium, if pressure increases (volume decreases), the system shifts to the side with fewer moles (particles) to counteract the pressure increase. But row A: pressure decreases (volume increases), so system shifts to more particles (to increase pressure). Wait, that's correct. Wait, no—Le Chatelier's principle: if pressure decreases (volume increases), the system shifts to the side with more moles (particles) to increase pressure. So when pressure (i) decreases, volume (ii) increases, and the system produces more particles (iii). That's row A. But the selected option is B. Wait, maybe the question is about when pressure increases (i), volume decreases (ii), what happens? If pressure increases, volume decreases, the system shifts to fewer particles. But row B says "more"—that would be incorrect. Wait, maybe the question is misphrased, or I misread. Wait, the original question: "When pressure i and volume ii the reaction in an equilibrium system shifts in the direction that produces iii particles." Let's analyze each row:
- Row A: i=decreases, ii=increases, iii=more. When pressure decreases (volume increases), the system shifts to more particles (to increase pressure) – this follows Le Chatelier.
- Row B: i=increases, ii=decreases, iii=more. When pressure increases (volume decreases), system should shift to fewer particles, not more – so B is wrong.
- Row C: i=decreases, ii=increases, iii=less – wrong, should be more.
- Row D: i=decreases, ii=increases, iii=same – wrong.
- Row E: i=increases, ii=decreases, iii=same – wrong.
Wait, but the selected option is B, but according to Le Chatelier, A should be correct. But maybe the question is about a different scenario? Wait, maybe the reaction has equal moles on both sides? No, the options have "more", "less", "same". Wait, perhaps the question is reversed. Wait, maybe the user made a mistake, but according to the options, the correct answer based on Le Chatelier (pressure decreases, volume increases, produces more particles) is row A. But the selected option is B. Wait, maybe I messed up. Wait, let's check again.
Wait, the key is: pressure and volume are inversely related (Boyle's law: \(P_1V_1 = P_2V_2\)). So if pressure (i) decreases, volume (ii) increases. Then, according to Le Chatelier, the system will shift to the side with more moles (particles) to increase the pressure (since pressure decreased). So that's row A: i=decreases, ii=increases, iii=more. So the correct answer should be A. But the selected option is B. Maybe the question was misprinted, or I have a misunderstanding. Alternatively, maybe the question is about when pressure increases (i), volume decreases (ii), and the system produces more particles – which would be incorrect, but perhaps the intended answer is A. However, the user's selected option is B, b…
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A. decreases, increases, more