Question

question 5
a box has a mass of 24 kilograms and sits on a ramp. the ramps surface is at an angle of 60 degrees from the horizontal. calculate the magnitude of the normal force exerted on the box by the ramp.

Explanation:

Step1: Calculate the weight of the box

The weight of the box \(W = mg\), where \(m = 24\space kg\) and \(g=9.8\space m/s^{2}\). So \(W=24\times9.8 = 235.2\space N\).

Step2: Resolve the weight into components

The normal force \(N\) is the component of the weight perpendicular to the ramp. If the angle of the ramp with the horizontal is \(\theta = 60^{\circ}\), then \(N = W\cos\theta\).
Substitute \(W = 235.2\space N\) and \(\theta = 60^{\circ}\) (and \(\cos60^{\circ}=0.5\)) into the formula: \(N=235.2\times0.5\).

Answer:

\(117.6000\)