Question

question 18
what is the output of the following code?
i = 1
while i <= 2:
j = 1
while j <= 3:
print(*, end = )
j += 1
print()
i += 1

Explanation:

Step1: Analyze the outer loop

The outer loop runs when \(i\leq2\). Initially \(i = 1\).

Step2: Analyze the inner loop for \(i = 1\)

When \(i = 1\), the inner loop \(j\) runs from \(1\) to \(3\). So, it prints ** (three s) and then print() makes a new line.

Step3: Update \(i\) and analyze for \(i = 2\)

\(i\) becomes \(2\). The inner loop again runs \(j\) from \(1\) to \(3\), prints *** and a new line. Then \(i\) becomes \(3\) and the outer loop stops.

Answer:

***
***