Question

question: 10
what would this program print?
x_pos = 16
y_pos = 20

computes the midpoint between (0,0)

and the point

def compute_distance(x_pos, y_pos):
print(\original point: \ + str(x_pos) + \, \ + str(y_pos))
print(\midpoint from origin: \ + str(x_pos/2) + \, \ + str(y_pos/2))

compute_distance(12, 14)
print(\point: \ + str(x_pos) + \, \ + str(y_pos))

Explanation:

Step1: Analyze function call

The function compute_distance is called with arguments 12 and 14. Inside the function, x_pos and y_pos in the function scope refer to these arguments. So, the first print statement in the function prints Original Point: 12, 14.

Step2: Calculate mid - point

For the mid - point calculation, x_pos/2 = 12/2=6.0 and y_pos/2 = 14/2 = 7.0. So, the second print statement in the function prints Midpoint from Origin: 6.0, 7.0.

Step3: Analyze the last print statement

After the function call, the last print statement accesses the global variables x_pos = 16 and y_pos = 20 (since the function call with local variables 12 and 14 does not change the global x_pos and y_pos). So, it prints Point: 16, 20.

Answer:

Original Point: 12, 14
Midpoint from Origin: 6.0, 7.0
Point: 16, 20