Question

q2. (3 points) show calculation of the photon energy for light from a green laser that has “λ = 532 nm” sketch one the side: (hint: do unit conversions, show units)
λ = 532 nm × = m.
e_ph =
q3. (4 points) complete the following table for various kind of light:

Explanation:

Step1: Convert wavelength from nm to m

We know that \(1\ nm = 1\times10^{-9}\ m\).
So, \(\lambda=532\ nm\times1\times 10^{-9}\frac{m}{nm}=532\times10^{-9}\ m = 5.32\times 10^{-7}\ m\)

Step2: Use the formula for photon energy \(E = h

u=\frac{hc}{\lambda}\)
where \(h = 6.626\times10^{-34}\ J\cdot s\) (Planck's constant) and \(c = 3\times10^{8}\ m/s\) (speed of light)

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Answer:

\(\lambda = 5.32\times 10^{-7}\ m\), \(E_{ph}=3.74\times 10^{-19}\ J\)