Question

1. a professional baseball player can pitch a baseball with a velocity of 44.7 m/s towards home plate. if a baseball weighs 1.4 n, how much momentum does it have when it hits the catchers mitt?

Explanation:

Step1: Calculate the mass of the baseball

We know that weight \(W = mg\), so \(m=\frac{W}{g}\). Given \(W = 1.4\ N\) and \(g=9.8\ m/s^{2}\), then \(m=\frac{1.4}{9.8}\ kg\).
$$m=\frac{1.4}{9.8}=\frac{1}{7}\ kg$$

Step2: Calculate the momentum

The formula for momentum is \(p = mv\). Given \(v = 44.7\ m/s\) and \(m=\frac{1}{7}\ kg\), then \(p=\frac{1}{7}\times44.7\ kg\cdot m/s\).
$$p=\frac{44.7}{7}\approx6.4\ kg\cdot m/s$$

Answer:

The momentum of the baseball is approximately \(6.4\ kg\cdot m/s\)