Question

problem 1
there are three forces exerting torques on a body. the body is in equilibrium.
one force exerts a torque of 5 nm, the second force give a torque of -9 nm.
find the torque due to the third force.

Explanation:

Step1: Recall the condition for rotational equilibrium

For a body in rotational equilibrium, the sum of torques \(\sum\tau = 0\). Let \(\tau_1 = 5\space Nm\), \(\tau_2=- 9\space Nm\) and \(\tau_3\) be the torques. Then \(\tau_1+\tau_2+\tau_3 = 0\).

Step2: Solve for \(\tau_3\)

Substitute the values of \(\tau_1\) and \(\tau_2\) into the equation \(\tau_3=-\tau_1 - \tau_2\).

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Answer:

\(4\space Nm\)