Question

practice

1. a rabbit runs 3.8 mn and stops to nibble on some grass. the rabbit then hops 6.3 mn to scratch against a small tree.

(a) sketch a diagram of the motion showing the displacement vectors and the total displacement vector.
(b) what is the rabbit’s total displacement?
(b) \\( \delta d _ { mathrm { t } } = 10.1 mathrm { m } mathrm { n } \\)

Explanation:

Step1: Analyze the direction of displacement

The rabbit moves in the same direction (north) for both parts of its motion.

Step2: Calculate the total displacement

Since displacement is a vector quantity and the directions are the same, we add the magnitudes of the two displacements.
$$\Delta d_T=\Delta d_1+\Delta d_2$$
Substitute $\Delta d_1 = 3.8\ m$ and $\Delta d_2=6.3\ m$ into the formula:
$$\Delta d_T=3.8 + 6.3$$
$$\Delta d_T = 10.1\ m$$
The direction remains north as the individual displacements are in the north direction.

Answer:

The rabbit's total displacement is $10.1\ m[N]$.