Question

1. -/4 points a ball is dropped from the top of a 91 - m - high building. what speed does the ball have in falling 3.0 s? m/s submit answer

Explanation:

Step1: Identify the kinematic equation

The kinematic equation for final velocity \(v = v_0+at\). Since the ball is dropped, \(v_0 = 0\ m/s\) and \(a = g= 9.8\ m/s^{2}\) (acceleration due to gravity).

Step2: Substitute the values

Substitute \(v_0 = 0\ m/s\), \(a = 9.8\ m/s^{2}\), and \(t = 3.0\ s\) into the equation \(v=v_0 + at\).

$$v=0+(9.8\times3.0)$$

$$v = 29.4\ m/s$$

Answer:

\(29.4\)