Question

a photon of light has an energy of 7.84 x 10^{-15} j, determine its frequency.

Explanation:

Step1: Recall the formula for photon energy

The energy of a photon is given by \(E = h
u\), where \(E\) is the energy, \(h\) is Planck's constant (\(h=6.626\times 10^{-34}\space J\cdot s\)), and \(
u\) is the frequency.

Step2: Solve for frequency \(

u\)
Rearrange the formula to \(
u=\frac{E}{h}\). Substitute \(E = 7.84\times 10^{-15}\space J\) and \(h = 6.626\times 10^{-34}\space J\cdot s\) into the formula:

$$ u=\frac{7.84\times 10^{-15}\space J}{6.626\times 10^{-34}\space J\cdot s} $$

$$ u=\frac{7.84}{6.626}\times10^{-15 + 34}\space Hz $$

$$ u\approx1.18\times 10^{19}\space Hz $$

Answer:

\(1.18\times 10^{19}\space Hz\)