a photon has a frequency of 7.3 × 10^{-17} hz. plancks constant is 6.63 × 10^{-34} j·s. the energy of the photon, to the nearest tenths place, is × 10^{-16} j.

Question

Accepted Answer

# Explanation:
## Step1: Recall the formula for photon energy
The energy of a photon is given by $E = h
u$, where $h$ is Planck's constant and $
u$ is the frequency.
## Step2: Substitute the given values
Given $h = 6.63\times10^{-34}\space J\cdot s$ and $
u=7.3\times 10^{17}\space Hz$.
$$
\begin{align*}
E&=(6.63\times 10^{-34})\times(7.3\times 10^{17})\
&=(6.63\times7.3)\times10^{-34 + 17}\
&=48.399\times10^{-17}\
&=4.8399\times 10^{-16}
\end{align*}
$$
## Step3: Round to the nearest tenths place
Rounding $4.8399$ to the nearest tenths place gives $4.8$.

# Answer:
$4.8$

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QUESTION IMAGE

Question

Explanation:

Step1: Recall the formula for photon energy

Step2: Substitute the given values

Step3: Round to the nearest tenths place

Answer: