Question

a person is riding on a ferris wheel. when the wheel makes one complete turn, the net work done on the person by the gravitational force ________. is zero is positive is negative depends on how fast the wheel moves depends on the diameter of the wheel

Explanation:

Step1: Recall work - energy theorem

Work done by a conservative force $W = -\Delta U$, where $\Delta U$ is the change in potential energy.

Step2: Analyze potential - energy change

Gravitational force is a conservative force. When the Ferris - wheel makes one complete turn, the person returns to the same height. So, $\Delta U = U_{f}-U_{i}=0$ (where $U = mgh$ and $h_{i}=h_{f}$).

Step3: Determine work done

Since $W = -\Delta U$ and $\Delta U = 0$, the work done by the gravitational force $W = 0$.

Answer:

A. is zero