Question

a particle with a charge of 3.00 elementary charges moves through a potential difference of 4.50 volts. what is the change in electrical potential energy of the

Explanation:

Step1: Recall the formula for electrical potential energy change

The formula for the change in electrical potential energy \(\Delta U\) is \(\Delta U = q\Delta V\), where \(q\) is the charge and \(\Delta V\) is the potential difference. Here, the charge \(q = 3.00e\) (in terms of elementary charges) and \(\Delta V=4.50\space V\).

Step2: Substitute the values into the formula

Since \(1\) elementary charge \(e\) moving through a potential difference of \(1\space V\) has an energy change of \(1\space eV\), when \(q = 3.00e\) and \(\Delta V = 4.50\space V\), we substitute into \(\Delta U=q\Delta V\). So \(\Delta U=(3.00)(4.50)\space eV\)

Step3: Calculate the result

\(3.00\times4.50 = 13.5\space eV\)

Answer:

C. \(13.5\space eV\)