Question

1. an object has an initial velocity of 4.0 m/s and a constant acceleration of 2.0 m/s². how far does the object travel in 20 s?

Explanation:

Step1: Identify the kinematic equation

We use the second kinematic equation for uniformly accelerated motion: $s = u t+\frac{1}{2} a t^{2}$, where $s$ is the displacement, $u$ is the initial velocity, $a$ is the acceleration, and $t$ is the time.

Step2: Substitute the given values

Given $u = 4.0\ m/s$, $a = 2.0\ m/s^{2}$, and $t = 20\ s$. Substitute these into the equation:

$$
LATEXBLOCK0
$$

Answer:

The object travels $\boldsymbol{480\ m}$ in 20 s.