Question

object ds motion can be described as __________. * 1 point
a
b
c
d
e
constant velocity
increasing velocity
decreasing velocity
no velocity
which time period on the velocity vs. time graph below represents dynamic equilibrium? * 1 point
stamp: how do we recognize acceleration on a velocity vs. time graph?
acceleration can be identified by seeing where velocity is changing over time. this includes where position is changing at a non - constant rate.
positive acceleration = velocity increasing
negative acceleration = velocity decreasing
zero acceleration = constant velocity
0 to 4 seconds
4 to 7 seconds
7 to 10 seconds
0 to 10 seconds

Explanation:

Step1: Analyze object D's motion

In the motion - diagram of object D, the dots are getting closer together over time. This indicates that the distance traveled in equal time intervals is decreasing. Since velocity is the rate of change of position with respect to time, a decreasing distance in equal time intervals means the velocity is decreasing.

Step2: Analyze the velocity - time graph for dynamic equilibrium

Dynamic equilibrium occurs when there is a non - zero constant velocity, which means zero acceleration. On a velocity - time graph, zero acceleration is represented by a horizontal line. In the given velocity - time graph, the horizontal line is in the time interval from 4 to 7 seconds.

Answer:

• For the first question: decreasing velocity
• For the second question: 4 to 7 seconds