Question

net force: n forces are: balanced unbalanced object will:

Explanation:

Assume the 55N force is at 45° (common if not specified; note: diagram angle unclear, but vertical/horizontal first):

Step1: Vertical net force

$F_{y} = 20N - 20N + 55\sin45° - 10\sin45° = 45\sin45° ≈ 31.82N$

Step2: Horizontal net force

$F_{x} = 55\cos45° - 10\cos45° = 45\cos45° ≈ 31.82N$

Step3: Total net force

$F_{net} = \sqrt{F_x^2 + F_y^2} ≈ \sqrt{(31.82)^2 + (31.82)^2} ≈ 45N$

Step4: Check balanced/unbalanced

$F_{net} ≠ 0$, so unbalanced.

Answer:

Net force: ~45 N
Forces are: unbalanced
Object will: accelerate in the direction of net force (northeast if 45° angle)