Question

multiple select question
select all that apply
suppose a force of 150 n is exerted on an object in the positive direction, and simultaneously a force of 200 n is exerted in the negative direction. how can the net force be described in this case?
50 n in the positive direction
50 n in the negative direction
+50 n
-50 n

Explanation:

Step1: Define positive and negative directions

Let the positive direction force \(F_1 = 150N\) and the negative direction force \(F_2=200N\).

Step2: Calculate the net force

The net force \(F_{net}=F_1 + F_2\). Substituting the values, \(F_{net}=150+( - 200)\) (since force in negative direction has a negative sign). Using the rule of addition of integers \(a+( - b)=a - b\), we get \(F_{net}=150 - 200=-50N\). The negative sign indicates the direction is negative.

Answer:

50 N in the negative direction, \(-50N\)